πŸ“š

Β >Β 

♾️ 

Β >Β 

πŸ€“

2.5 Applying the Power Rule

3 min readβ€’june 18, 2024

2.5 Applying the Power Rule

Welcome back to AP Calculus with Fiveable! We are now diving into one of the most valuable fundamental concepts in calculus: the Power Rule. This is the first of many derivative rules that you’re going to learn about!

⚑ The Power Rule

The Power Rule states that if f(x)=xnf(x) = x^n, where nn is constant, then the derivative fβ€²(x)f'(x) is given by:

fβ€²(x)=nβ‹…x(nβˆ’1) f'(x) = n \cdot x^{(n-1)}

So, the Power Rule provides a shortcut for finding the derivative without using the limit definition of a derivative. Wasn’t doing that annoying?!


πŸ‹οΈβ€β™‚οΈΒ Practice Problems****

Let’s work on a few questions to get the Power Rule down!

  1. Given f(x)=x4f(x) = x^4, find fβ€²(x)f'(x).
  2. Given f(x)=1x5f(x) = \frac{1}{x^5}, find fβ€²(x)f'(x).
  3. Given f(x)=xf(x) = \sqrt{x}, find fβ€²(x)f'(x).
  4. Given f(x)=x6+2x4βˆ’10f(x) = x^6 +2x^4-10, find fβ€²(x)f'(x).

πŸ’‘ Before we reveal the answers, remember:

  1. The Power Rule with fractions can be tricky! Sometimes rewriting the equation can help.
  2. The derivative of any constant is zero.

πŸ‘€ Answers to Practice Problems

Note how for many of these problems, the equations were rewritten before solving for the derivative using the power rule.

  1. fβ€²(x)=4β‹…x(4βˆ’1)f'(x) = 4 \cdot x^{(4-1)} =4x3= 4x^3

  2. f(x)=xβˆ’5f(x) = x^{-5}

    fβ€²(x)=βˆ’5β‹…x(βˆ’5βˆ’1)f'(x) = -5 \cdot x^{(-5-1)} =βˆ’5xβˆ’6= -5x^{-6} =βˆ’5x6= \frac{-5}{x^{6}}

  3. f(x)=x1/2f(x) = x^{1/2}

    fβ€²(x)=12β‹…xβˆ’12f'(x) = \frac{1}{2} \cdot x^\frac{-1}{2} =12x= \frac {1}{2\sqrt{x}}

  4. fβ€²(x)=6x5+8x3f'(x)=6x^5 + 8x^3

Yep! That’s it. This lesson was super short. Want to jump into the rest of the derivative rules you have to know? ⏭️

<< Hide Menu

πŸ“š

Β >Β 

♾️ 

Β >Β 

πŸ€“

2.5 Applying the Power Rule

3 min readβ€’june 18, 2024

2.5 Applying the Power Rule

Welcome back to AP Calculus with Fiveable! We are now diving into one of the most valuable fundamental concepts in calculus: the Power Rule. This is the first of many derivative rules that you’re going to learn about!

⚑ The Power Rule

The Power Rule states that if f(x)=xnf(x) = x^n, where nn is constant, then the derivative fβ€²(x)f'(x) is given by:

fβ€²(x)=nβ‹…x(nβˆ’1) f'(x) = n \cdot x^{(n-1)}

So, the Power Rule provides a shortcut for finding the derivative without using the limit definition of a derivative. Wasn’t doing that annoying?!


πŸ‹οΈβ€β™‚οΈΒ Practice Problems****

Let’s work on a few questions to get the Power Rule down!

  1. Given f(x)=x4f(x) = x^4, find fβ€²(x)f'(x).
  2. Given f(x)=1x5f(x) = \frac{1}{x^5}, find fβ€²(x)f'(x).
  3. Given f(x)=xf(x) = \sqrt{x}, find fβ€²(x)f'(x).
  4. Given f(x)=x6+2x4βˆ’10f(x) = x^6 +2x^4-10, find fβ€²(x)f'(x).

πŸ’‘ Before we reveal the answers, remember:

  1. The Power Rule with fractions can be tricky! Sometimes rewriting the equation can help.
  2. The derivative of any constant is zero.

πŸ‘€ Answers to Practice Problems

Note how for many of these problems, the equations were rewritten before solving for the derivative using the power rule.

  1. fβ€²(x)=4β‹…x(4βˆ’1)f'(x) = 4 \cdot x^{(4-1)} =4x3= 4x^3

  2. f(x)=xβˆ’5f(x) = x^{-5}

    fβ€²(x)=βˆ’5β‹…x(βˆ’5βˆ’1)f'(x) = -5 \cdot x^{(-5-1)} =βˆ’5xβˆ’6= -5x^{-6} =βˆ’5x6= \frac{-5}{x^{6}}

  3. f(x)=x1/2f(x) = x^{1/2}

    fβ€²(x)=12β‹…xβˆ’12f'(x) = \frac{1}{2} \cdot x^\frac{-1}{2} =12x= \frac {1}{2\sqrt{x}}

  4. fβ€²(x)=6x5+8x3f'(x)=6x^5 + 8x^3

Yep! That’s it. This lesson was super short. Want to jump into the rest of the derivative rules you have to know? ⏭️