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Hope Arnett
Dalia Savy
Hope Arnett
Dalia Savy
Titrations are an experimental method🧪 used to determine the unknown concentration of a chemical solution. There are two key substances in a titration: the titrant and the analyte.
Don't worry about the other types of titrations! Let's dig deeper into acid-base titrations.
The titrant in the burette is typically a strong acid or base (and remember, we know its concentration 🍊). The analyte of unknown concentration is in the Erlenmeyer flask beneath the burette and is usually a weak acid or base.
Both the burette and Erlenmeyer flask have tick marks for measurement, so we know the initial volumes of both solutions and can do the necessary math to solve for the molarity of the analyte. Remember, molarity (M) is a measure of concentration and can be calculated by dividing the moles of the substance by its volume in liters. This is why we need to keep a record of how much solution is used.
Along with the weak acid or base, the Erlenmeyer has a drop or two of an indicator. There are different types of indicators, and each indicator changes the solution’s color when it is within a certain pH range.
When you a preparing a titration, you:
A common indicator is phenolphthalein, which makes the solution light-pink at the equivalence point. If the analyte is a weak acid and the titrant is a strong base, the pH of the analyte is less than 7 before the titration begins. At this point, the phenolphthalein makes the solution colorless. However, as the base is added, the solution's pH increases. At the endpoint, once a certain amount of strong base is added, the solution changes color.
Below is a sample graph of the curve:
Since the equivalence point is when the number of moles of acid and base are equal, we can make an equation using molarity (moles/L) and volume:
moles of acid = moles of base
Since moles = molarity x liters, we can say that the molarity of the titrant times the volume of the titrant equals the molarity of the analyte times the volume of the analyte or MaVa = MbVb.
We know the titrant’s concentration going into the titration, so we can use that for Ma. Va is the amount of titrant added to the Erlenmeyer flask. Vb is the analyte’s initial volume. We can plug in these values and then solve for Mb.
** It’s important to note that if the mole ratio of the acid and base is NOT 1:1, then you would need to multiply the appropriate sides by their mole ratio. For example, if an acid and base have a mole ratio of 1:2, then this would be the equation: MaVa = 2MbVb**
The following question is from the Advanced Placement YT Channel.
A solution of vinegar contains an unknown amount of acetic acid, HC₂H₃O₂. A 25.0 mL sample of vinegar is titrated with 0.650 M NaOH according to the chemical reaction below. If it requires 32.04 mL of the titrant to reach the equivalence point, what is the concentration of HC₂H₃O₂ in the vinegar?
HC₂H₃O₂ (aq) + NaOH (aq) → H₂O (l) + NaC₂H₃O₂ (aq)
This requires the simple use of MaVa = MbVb. Since the mole ratio is 1:1, we can just plug in and solve!🎉
(Ma)(25.0 mL) =(0.650 M)(32.04 mL)
Ma = 0.833 M
Acid-base reaction equations illustrate what is happening during titrations. In the Brønsted-Lowry definition, acids are proton donors and bases are proton acceptors. The species that donated the proton becomes the acid’s conjugate base. Similarly, the species that accepted the proton is now the conjugate acid.
By looking at chemical equations, we can identify which species are the acid, base, conjugate acid, and conjugate base. Check out the example below:
HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O (l)
Take a look at the reactants and the products. Notice that this is a double replacement reaction. The reactants’ ions split up, and the H⁺ from HCl joined with OH⁻ to make water. The remaining ions are then combined.
Since HCl gave up its proton, and hydroxide from NaOH accepted it, HCl is the acid, and NaOH is the base. Their corresponding products are their conjugates.
There is a quick way to figure out the conjugate acid and base! First, find the pairs!
Let's use NH₃ + H₂O → NH₄⁺ + OH⁻ as the example.
NH₃ and NH₄⁺ are the first pair.
H₂O and OH⁻ are the second pair.
But how do we know which one is the acid and which one is the base in each pair?💭
Simple! The compound with the extra hydrogen is the acid. Therefore, NH₄⁺ is the conjugate acid and H₂O is the acid.
Identify the acid and base and their conjugates.
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Hope Arnett
Dalia Savy
Hope Arnett
Dalia Savy
Titrations are an experimental method🧪 used to determine the unknown concentration of a chemical solution. There are two key substances in a titration: the titrant and the analyte.
Don't worry about the other types of titrations! Let's dig deeper into acid-base titrations.
The titrant in the burette is typically a strong acid or base (and remember, we know its concentration 🍊). The analyte of unknown concentration is in the Erlenmeyer flask beneath the burette and is usually a weak acid or base.
Both the burette and Erlenmeyer flask have tick marks for measurement, so we know the initial volumes of both solutions and can do the necessary math to solve for the molarity of the analyte. Remember, molarity (M) is a measure of concentration and can be calculated by dividing the moles of the substance by its volume in liters. This is why we need to keep a record of how much solution is used.
Along with the weak acid or base, the Erlenmeyer has a drop or two of an indicator. There are different types of indicators, and each indicator changes the solution’s color when it is within a certain pH range.
When you a preparing a titration, you:
A common indicator is phenolphthalein, which makes the solution light-pink at the equivalence point. If the analyte is a weak acid and the titrant is a strong base, the pH of the analyte is less than 7 before the titration begins. At this point, the phenolphthalein makes the solution colorless. However, as the base is added, the solution's pH increases. At the endpoint, once a certain amount of strong base is added, the solution changes color.
Below is a sample graph of the curve:
Since the equivalence point is when the number of moles of acid and base are equal, we can make an equation using molarity (moles/L) and volume:
moles of acid = moles of base
Since moles = molarity x liters, we can say that the molarity of the titrant times the volume of the titrant equals the molarity of the analyte times the volume of the analyte or MaVa = MbVb.
We know the titrant’s concentration going into the titration, so we can use that for Ma. Va is the amount of titrant added to the Erlenmeyer flask. Vb is the analyte’s initial volume. We can plug in these values and then solve for Mb.
** It’s important to note that if the mole ratio of the acid and base is NOT 1:1, then you would need to multiply the appropriate sides by their mole ratio. For example, if an acid and base have a mole ratio of 1:2, then this would be the equation: MaVa = 2MbVb**
The following question is from the Advanced Placement YT Channel.
A solution of vinegar contains an unknown amount of acetic acid, HC₂H₃O₂. A 25.0 mL sample of vinegar is titrated with 0.650 M NaOH according to the chemical reaction below. If it requires 32.04 mL of the titrant to reach the equivalence point, what is the concentration of HC₂H₃O₂ in the vinegar?
HC₂H₃O₂ (aq) + NaOH (aq) → H₂O (l) + NaC₂H₃O₂ (aq)
This requires the simple use of MaVa = MbVb. Since the mole ratio is 1:1, we can just plug in and solve!🎉
(Ma)(25.0 mL) =(0.650 M)(32.04 mL)
Ma = 0.833 M
Acid-base reaction equations illustrate what is happening during titrations. In the Brønsted-Lowry definition, acids are proton donors and bases are proton acceptors. The species that donated the proton becomes the acid’s conjugate base. Similarly, the species that accepted the proton is now the conjugate acid.
By looking at chemical equations, we can identify which species are the acid, base, conjugate acid, and conjugate base. Check out the example below:
HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O (l)
Take a look at the reactants and the products. Notice that this is a double replacement reaction. The reactants’ ions split up, and the H⁺ from HCl joined with OH⁻ to make water. The remaining ions are then combined.
Since HCl gave up its proton, and hydroxide from NaOH accepted it, HCl is the acid, and NaOH is the base. Their corresponding products are their conjugates.
There is a quick way to figure out the conjugate acid and base! First, find the pairs!
Let's use NH₃ + H₂O → NH₄⁺ + OH⁻ as the example.
NH₃ and NH₄⁺ are the first pair.
H₂O and OH⁻ are the second pair.
But how do we know which one is the acid and which one is the base in each pair?💭
Simple! The compound with the extra hydrogen is the acid. Therefore, NH₄⁺ is the conjugate acid and H₂O is the acid.
Identify the acid and base and their conjugates.
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