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Krish Gupta
Daniella Garcia-Loos
Krish Gupta
Daniella Garcia-Loos
A capacitor is a device that can be used to store charge, and therefore, electrical potential energy. They are used in a wide range of electrical devices including the flash on your cell phone camera. There are several different ways to construct a capacitor, but we're going to focus on the parallel-plate version.
A capacitor is a device that stores electric charge and energy in an electric field. It consists of two conductors, called plates, separated by an insulating material called the dielectric.
Here are some key points about capacitors:
Let's create a simple capacitor using two metal plates and connect them to a battery to charge them up. Recall from Unit 1, that the strength of the electric field is proportional to the amount charge. E=kQ/r^2
Let's derive what capacitance actually is. This derivation is beyond the course but will give you a deeper understanding of circuits.
We can also define capacitance in terms of the physical dimensions of the capacitor. Recall that σ=Q/A (area charge density) for a sheet of charge, and E=σ/ϵ0 for a conductive plate.
From here, we can see that capacitance is directly proportional to the area of the plates (A) and inversely proportional to the distance between them. This should make sense since a larger plate has more room for the charge to occupy and, therefore, more should be able to fit on it.
Because the capacitor stores charge, it also stores electric potential energy (UC). The amount of energy stored can be determined through a derivation. However, the derivation requires understanding of integral calculus we will just work with the final product.
Here are some key points about energy in a capacitor:
Take a few minutes and check out this Phet Simulation where you can alter the physical properties of a parallel plate capacitor and see the effect on voltage, field strength, and energy stored.
Dielectrics are insulating materials that are often used in capacitors to increase their capacitance. They help solve the problem of how to get more charge into a capacitor without having the voltage decrease. C=Aϵo/d. Modifying the equation to include a dielectric involves adding a new term κ, which is the dielectric constant. In general, the easier a material is to polarize, the higher it's dielectric constant is. Values for common dielectrics are shown below:
Material | Dielectric Constant |
Vacuum | 1 |
Air | 1.00059 |
Bakelite | 4.9 |
Fused Quartz | 3.78 |
Neoprene Rubber | 6.7 |
Nylon | 3.4 |
Paper | 3.7 |
Polystyrene | 2.56 |
Pyrex Glass | 5.6 |
Silicon Oil | 2.5 |
Strontium Titanate | 233 |
Teflon | 2.1 |
Water | 80 |
Great question! It's because a dielectric becomes polarized easily. In fact, the easier the dielectric becomes polarized, the greater its κ becomes. Let's look at an image to understand why the polarization helps increase the capacitance.
In image (a), we can see that the molecules of the dielectric become polarized and align opposing the charge on the plates. This produces a layer of opposite charge on the surface of the dielectric that attracts more charge onto the plate, because of Coulomb's Law, increasing its capacitance.
Another way to understand how a dielectric increases capacitance is to look at how it changes the electric field inside the capacitor. Image (b) shows the electric field lines with a dielectric in place. Since some of the field lines end on charges in the dielectric (because the polarity of the dielectric is opposite that of the plates), the overall field between the plates is weaker than if there were a vacuum between the plates, even though the same charge is on the plates.
The voltage between the plates is V=Ed, so it is also reduced by the dielectric. This means there is a smaller V for the same charge Q and since C = Q/V, the capacitance is greater.
** After looking back at 20+ years of FRQs, if you see an FRQ on circuits, there's a really good chance it will have a capacitor in it. You've been warned 🙂**
Capacitors have their own special equations for determining equivalent resistance in series or parallel, just like resistors.
For example, in the circuit below, the current initially flows through both branches, but as the voltage of C1 approaches the battery voltage, less and less current passes through R1. When steady state is reached, the circuit will appear to be a series circuit with only R2 in it.
An RC circuit is a type of electrical circuit that contains a resistor and a capacitor connected in series or parallel. RC circuits are used to filter signals, smooth out voltage fluctuations, and discharge stored energy.
Here are some key points about RC circuits:
Knowing the exact equations or graphs of RC Circuit equations in not on the exam but will help enhance your understanding. Graphing these functions shows us the changes in V and I as the capacitor charges. Notice how when the steady-state is reached, the current in the capacitor is basically zero.
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Krish Gupta
Daniella Garcia-Loos
Krish Gupta
Daniella Garcia-Loos
A capacitor is a device that can be used to store charge, and therefore, electrical potential energy. They are used in a wide range of electrical devices including the flash on your cell phone camera. There are several different ways to construct a capacitor, but we're going to focus on the parallel-plate version.
A capacitor is a device that stores electric charge and energy in an electric field. It consists of two conductors, called plates, separated by an insulating material called the dielectric.
Here are some key points about capacitors:
Let's create a simple capacitor using two metal plates and connect them to a battery to charge them up. Recall from Unit 1, that the strength of the electric field is proportional to the amount charge. E=kQ/r^2
Let's derive what capacitance actually is. This derivation is beyond the course but will give you a deeper understanding of circuits.
We can also define capacitance in terms of the physical dimensions of the capacitor. Recall that σ=Q/A (area charge density) for a sheet of charge, and E=σ/ϵ0 for a conductive plate.
From here, we can see that capacitance is directly proportional to the area of the plates (A) and inversely proportional to the distance between them. This should make sense since a larger plate has more room for the charge to occupy and, therefore, more should be able to fit on it.
Because the capacitor stores charge, it also stores electric potential energy (UC). The amount of energy stored can be determined through a derivation. However, the derivation requires understanding of integral calculus we will just work with the final product.
Here are some key points about energy in a capacitor:
Take a few minutes and check out this Phet Simulation where you can alter the physical properties of a parallel plate capacitor and see the effect on voltage, field strength, and energy stored.
Dielectrics are insulating materials that are often used in capacitors to increase their capacitance. They help solve the problem of how to get more charge into a capacitor without having the voltage decrease. C=Aϵo/d. Modifying the equation to include a dielectric involves adding a new term κ, which is the dielectric constant. In general, the easier a material is to polarize, the higher it's dielectric constant is. Values for common dielectrics are shown below:
Material | Dielectric Constant |
Vacuum | 1 |
Air | 1.00059 |
Bakelite | 4.9 |
Fused Quartz | 3.78 |
Neoprene Rubber | 6.7 |
Nylon | 3.4 |
Paper | 3.7 |
Polystyrene | 2.56 |
Pyrex Glass | 5.6 |
Silicon Oil | 2.5 |
Strontium Titanate | 233 |
Teflon | 2.1 |
Water | 80 |
Great question! It's because a dielectric becomes polarized easily. In fact, the easier the dielectric becomes polarized, the greater its κ becomes. Let's look at an image to understand why the polarization helps increase the capacitance.
In image (a), we can see that the molecules of the dielectric become polarized and align opposing the charge on the plates. This produces a layer of opposite charge on the surface of the dielectric that attracts more charge onto the plate, because of Coulomb's Law, increasing its capacitance.
Another way to understand how a dielectric increases capacitance is to look at how it changes the electric field inside the capacitor. Image (b) shows the electric field lines with a dielectric in place. Since some of the field lines end on charges in the dielectric (because the polarity of the dielectric is opposite that of the plates), the overall field between the plates is weaker than if there were a vacuum between the plates, even though the same charge is on the plates.
The voltage between the plates is V=Ed, so it is also reduced by the dielectric. This means there is a smaller V for the same charge Q and since C = Q/V, the capacitance is greater.
** After looking back at 20+ years of FRQs, if you see an FRQ on circuits, there's a really good chance it will have a capacitor in it. You've been warned 🙂**
Capacitors have their own special equations for determining equivalent resistance in series or parallel, just like resistors.
For example, in the circuit below, the current initially flows through both branches, but as the voltage of C1 approaches the battery voltage, less and less current passes through R1. When steady state is reached, the circuit will appear to be a series circuit with only R2 in it.
An RC circuit is a type of electrical circuit that contains a resistor and a capacitor connected in series or parallel. RC circuits are used to filter signals, smooth out voltage fluctuations, and discharge stored energy.
Here are some key points about RC circuits:
Knowing the exact equations or graphs of RC Circuit equations in not on the exam but will help enhance your understanding. Graphing these functions shows us the changes in V and I as the capacitor charges. Notice how when the steady-state is reached, the current in the capacitor is basically zero.
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