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8 min read•july 22, 2024
Daniella Garcia-Loos
Saarah Hasan
Daniella Garcia-Loos
Saarah Hasan
Atoms. The smallest and most basic units of matter and the defining structure of elements. In this lesson, we’re going to go over what an atom is made up of, atomic theory, and electron energy levels. After going through this unit you should be able to discuss the internal structure of atoms and their nuclei.
Let’s go over our understanding of what an atom is. Some general information about atoms:
Particle | |||
Electron | e- | 9.11*10^-31 | -1.6*10^-19 |
Proton | p | 1.673*10^-27 | 1.6*10^19 |
Neutron | n | 1.673*10^-27 | No charge! |
Electrons, neutrinos, photons, and quarks are examples of fundamental particles: particles that make up other particles but can’t be broken down (they aren’t composed of other particles). Neutrons and protons are composed of quarks, which have electric charges that are fractions of the elementary charge of the electron.
There are 6 types (flavors) of quarks: up, down, strange, charm, bottom, and top.
The nucleus of the atom is composed of protons and neutrons, which are collectively called nucleons. The number of protons in a nucleus is the atom’s atomic number (Z)—it’s sort of the identifier of an element. Adding the number of neutrons (N) and the number of protons gives the mass number (A) of an element.
Nuclei that contain the same numbers of protons but a different number of neutrons are called isotopes.
If you’ve taken chemistry, you’re probably familiar with Ernest Rutherford. Rutherford was a physicist who decided to test out J.J. Thompson’s model of an atom, which proposed that an atom consisted of a relatively large, uniformly distributed, positive mass with negatively charged electrons embedded throughout the atom.
Rutherford’s experiment consisted of aiming alpha particles at a thin sheet of gold foil and observing the scattering pattern on a zinc sulfide screen. Rutherford found that while most of the alpha particles weren’t deflected, some were strongly deflected in hyperbolic paths, and a few were even scattered back close to 180^o180o.
Rutherford concluded that the atom consisted of mostly empty space, the nucleus was a very small, densely packed, positive charge, and the electrons orbited around the nucleus like planets orbiting the Sun.
His proposition, however, had several major problems:
Years after Rutherford’s declaration of his nuclear model of the atom, a physicist named Niels Bohr set out to add an important piece to the atomic puzzle.
Bohr realized that the Balmer formula, which essentially summarizes the visible wavelengths that appear in the emission spectrum of hydrogen, could be looked at in terms of energy differences. The main takeaways:
Here are some key differences between Bohr and Rutherford's models of the atom:
Let’s zoom in really quick on the nucleus of an atom. Aren’t the protons experiencing a repulsive Coulomb’s force from each other? What’s holding the nucleus together? Well, the presence of another fundamental force stronger than Coulomb’s force is the reason: the strong nuclear force (yes, it’s really called that). The strong nuclear force binds the neutrons and protons together; it’s the strongest force in nature.
Okay, now back to the Bohr Model of the Atom. Remember how we said that an electron has a certain set orbit? Well, if the electron absorbs a certain amount of energy, it gets excited to a higher orbit with a greater radius. After some time, it returns to a lower orbit, emitting a photon while doing so. Since each allowed orbit (energy level) has a specific radius and energy, the photons in each jump have only specific wavelengths.
When the excited electron drops from energy level n=jn=j to a lower one, n=in=i, the energy of the photon emitted is the difference between the two energy levels:
E*(emitted photon)*=|ΔE|=E_j-E_i
The wavelength of this photon is
λ=c/f=c/(Ephoton/h)=hc/(Ej-Ei)
where
c= speed of light =3.00*10^8
h= Planck's' constant = 6.6310^-^3^4 Js
Let's look at a practice problem together.
(A) Looking at the energy level diagram for hydrogen above (ignore the Ly equations near the arrows), how much energy must a ground-state electron in a hydrogen atom absorb to be excited to the n=3 energy level?
(B) If an electron jumped to n=4 level, what wavelengths are possible for the photon emitted when the electron drops to a lower energy level? In what regions of the EM spectrum do these photons lie?
(A)
The ground state energy level (n=1) is -13.6 eV and E_3=-1.51 eV.
The energy needed for an electron to jump from E1 to E3:
E_3-E_1=(-1.51 eV)-(-13.6 eV)= 12.09
(B) An electron in the n=4 energy level can drop to n=3, n=2, or all the way down to n=1. The energies of the n=2 and n=3n=3 levels are
E_2=1/2^2(-13.6 eV)=-3.4 eV
E_3=1/3^2(-13.6)=-1.5eV
The 3 possible values for the energy of the emitted photon:
E_4_→_3=E_4-E_3=(-0.85 eV)-(-1.5 eV)=0.65eV
E_4_→_2=E_4-E_2=(-0.85 eV)-(-3.4 eV)=2.55eV
E_4_→_1=E_4-E_1=(-0.85 eV)-(-13.6 eV) 12.8 eV
From the equation E=hf=hc/λ, we get λ=hc/E
λ_4_→_3=(4.1410^-^1^5 eVs)(3.00*10^8 m/s)/(0.65 eV)= 1,910 nm
➡️ In the visible light spectrum; the wavelength matches to the color blue-green
λ_4_→_2=(4.1410^-^1^5 eVs)(3.00*10^8 m/s)/(2.55 eV)=487 nm
➡️ Ultraviolet wavelength
λ_4_→_1=(4.1410^-^1^5 eVs)(3.00*10^8 m/s)/(12.8 eV)=97 nm
➡️Infrared
A) 7
B) 6
C) 5
D) 4
E) 3
A) The nucleus must have a positive charge
B) Most of the mass of an atom is in the nucleus
C) The nucleus contains both protons and neutrons
D) The diameter of the nucleus is small compared to the diameter of the atom
E) none of the above.
A) the positively charged nucleus attracts the electrons
B) Coulomb's law applies
C) accelerating electrons radiate energy
D) there is a centripetal force on the electrons
E) angular momentum is conserved
B) 2 eV
C) 3 eV
D) 4 eV
E) 5 eV
A) n = 2 to n = 1
B) n = 3 to n = 1
C) n = 3 to n = 2
D) n = 4 to n = 1
E) n = 4 to n = 3
Answers:
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8 min read•july 22, 2024
Daniella Garcia-Loos
Saarah Hasan
Daniella Garcia-Loos
Saarah Hasan
Atoms. The smallest and most basic units of matter and the defining structure of elements. In this lesson, we’re going to go over what an atom is made up of, atomic theory, and electron energy levels. After going through this unit you should be able to discuss the internal structure of atoms and their nuclei.
Let’s go over our understanding of what an atom is. Some general information about atoms:
Particle | |||
Electron | e- | 9.11*10^-31 | -1.6*10^-19 |
Proton | p | 1.673*10^-27 | 1.6*10^19 |
Neutron | n | 1.673*10^-27 | No charge! |
Electrons, neutrinos, photons, and quarks are examples of fundamental particles: particles that make up other particles but can’t be broken down (they aren’t composed of other particles). Neutrons and protons are composed of quarks, which have electric charges that are fractions of the elementary charge of the electron.
There are 6 types (flavors) of quarks: up, down, strange, charm, bottom, and top.
The nucleus of the atom is composed of protons and neutrons, which are collectively called nucleons. The number of protons in a nucleus is the atom’s atomic number (Z)—it’s sort of the identifier of an element. Adding the number of neutrons (N) and the number of protons gives the mass number (A) of an element.
Nuclei that contain the same numbers of protons but a different number of neutrons are called isotopes.
If you’ve taken chemistry, you’re probably familiar with Ernest Rutherford. Rutherford was a physicist who decided to test out J.J. Thompson’s model of an atom, which proposed that an atom consisted of a relatively large, uniformly distributed, positive mass with negatively charged electrons embedded throughout the atom.
Rutherford’s experiment consisted of aiming alpha particles at a thin sheet of gold foil and observing the scattering pattern on a zinc sulfide screen. Rutherford found that while most of the alpha particles weren’t deflected, some were strongly deflected in hyperbolic paths, and a few were even scattered back close to 180^o180o.
Rutherford concluded that the atom consisted of mostly empty space, the nucleus was a very small, densely packed, positive charge, and the electrons orbited around the nucleus like planets orbiting the Sun.
His proposition, however, had several major problems:
Years after Rutherford’s declaration of his nuclear model of the atom, a physicist named Niels Bohr set out to add an important piece to the atomic puzzle.
Bohr realized that the Balmer formula, which essentially summarizes the visible wavelengths that appear in the emission spectrum of hydrogen, could be looked at in terms of energy differences. The main takeaways:
Here are some key differences between Bohr and Rutherford's models of the atom:
Let’s zoom in really quick on the nucleus of an atom. Aren’t the protons experiencing a repulsive Coulomb’s force from each other? What’s holding the nucleus together? Well, the presence of another fundamental force stronger than Coulomb’s force is the reason: the strong nuclear force (yes, it’s really called that). The strong nuclear force binds the neutrons and protons together; it’s the strongest force in nature.
Okay, now back to the Bohr Model of the Atom. Remember how we said that an electron has a certain set orbit? Well, if the electron absorbs a certain amount of energy, it gets excited to a higher orbit with a greater radius. After some time, it returns to a lower orbit, emitting a photon while doing so. Since each allowed orbit (energy level) has a specific radius and energy, the photons in each jump have only specific wavelengths.
When the excited electron drops from energy level n=jn=j to a lower one, n=in=i, the energy of the photon emitted is the difference between the two energy levels:
E*(emitted photon)*=|ΔE|=E_j-E_i
The wavelength of this photon is
λ=c/f=c/(Ephoton/h)=hc/(Ej-Ei)
where
c= speed of light =3.00*10^8
h= Planck's' constant = 6.6310^-^3^4 Js
Let's look at a practice problem together.
(A) Looking at the energy level diagram for hydrogen above (ignore the Ly equations near the arrows), how much energy must a ground-state electron in a hydrogen atom absorb to be excited to the n=3 energy level?
(B) If an electron jumped to n=4 level, what wavelengths are possible for the photon emitted when the electron drops to a lower energy level? In what regions of the EM spectrum do these photons lie?
(A)
The ground state energy level (n=1) is -13.6 eV and E_3=-1.51 eV.
The energy needed for an electron to jump from E1 to E3:
E_3-E_1=(-1.51 eV)-(-13.6 eV)= 12.09
(B) An electron in the n=4 energy level can drop to n=3, n=2, or all the way down to n=1. The energies of the n=2 and n=3n=3 levels are
E_2=1/2^2(-13.6 eV)=-3.4 eV
E_3=1/3^2(-13.6)=-1.5eV
The 3 possible values for the energy of the emitted photon:
E_4_→_3=E_4-E_3=(-0.85 eV)-(-1.5 eV)=0.65eV
E_4_→_2=E_4-E_2=(-0.85 eV)-(-3.4 eV)=2.55eV
E_4_→_1=E_4-E_1=(-0.85 eV)-(-13.6 eV) 12.8 eV
From the equation E=hf=hc/λ, we get λ=hc/E
λ_4_→_3=(4.1410^-^1^5 eVs)(3.00*10^8 m/s)/(0.65 eV)= 1,910 nm
➡️ In the visible light spectrum; the wavelength matches to the color blue-green
λ_4_→_2=(4.1410^-^1^5 eVs)(3.00*10^8 m/s)/(2.55 eV)=487 nm
➡️ Ultraviolet wavelength
λ_4_→_1=(4.1410^-^1^5 eVs)(3.00*10^8 m/s)/(12.8 eV)=97 nm
➡️Infrared
A) 7
B) 6
C) 5
D) 4
E) 3
A) The nucleus must have a positive charge
B) Most of the mass of an atom is in the nucleus
C) The nucleus contains both protons and neutrons
D) The diameter of the nucleus is small compared to the diameter of the atom
E) none of the above.
A) the positively charged nucleus attracts the electrons
B) Coulomb's law applies
C) accelerating electrons radiate energy
D) there is a centripetal force on the electrons
E) angular momentum is conserved
B) 2 eV
C) 3 eV
D) 4 eV
E) 5 eV
A) n = 2 to n = 1
B) n = 3 to n = 1
C) n = 3 to n = 2
D) n = 4 to n = 1
E) n = 4 to n = 3
Answers:
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