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Kashvi Panjolia
Kashvi Panjolia
In the past few guides, we have been focusing on sinusoidal functions -- functions that look like the sine and cosine curves. In this guide, we will return to the unit circle to explore a third function that is not sinusoidal -- the tangent function. Then, we'll put together the ideas we learned about the transformation of sinusoidal functions and see how they apply to the non-sinusoidal function of tangent.
The tangent function, denoted by the symbol "tan", is a trigonometric function that is commonly used in mathematics and physics. It is defined as the ratio of the length of the side opposite a given angle in a right triangle to the length of the side adjacent to that angle. In other words, if a right triangle has an angle θ, with opposite side y and adjacent side x, the tangent of that angle is defined as tan(θ) = y/x.
x = cos(θ) and y = sin(θ)
Like we did for sine and cosine, let's understand the behavior of the tangent function using patterns we find on the unit circle. As we move around the unit circle, the value of θ changes, and the coordinates (x, y) change. As a result, the equation f(θ) = tan(θ) traces out the graph of the tangent function. Starting at the 0-degree mark, and moving counterclockwise, we can see that the values for sin(θ)/cos(θ) are increasingly positive for the first quadrant. At θ = 𝛑/2, the value of sin(θ)/cos(θ) is 1/0, so the slope is--
Wait. We can't divide by 0!
This is where the behavior of the tangent function differs from sine and cosine. As you probably learned in algebra, the slope of a vertical line, such as the one created by the terminal ray at θ = 𝛑/2, is undefined. This means that at θ = 𝛑/2, there is a vertical asymptote in the graph of tangent. We'll come back to this in a moment. Let's continue analyzing the patterns we see in the unit circle.
Moving from θ = 𝛑/2 to θ = 𝛑, we see that the tangent values are negative, but increasing towards 0. In the third quadrant, the tangent values are positive (again?) because a negative divided by a negative becomes positive. At θ = 3𝛑/2, we have to divide -1 by 0, which is, again, not possible, so our slope is once again undefined. In the fourth quadrant, the values of tangent are once again negative and increasing.
Recall that the slope of the terminal ray is equal to the tangent of the angle. If you zoom out and look at the unit circle as a whole, you'll notice that the angles θ = 𝛑/6 and θ = 7𝛑/6 lie along the same line. This means that the two terminal rays pointing to these two angles have the same slope, and therefore, the tangent value of these two angles is the same. Based on this observation, the tangent function repeats every half-rotation around the unit circle, so it has a period of 𝛑, whereas the sine and cosine functions had a period of 2𝛑.
Now that we have learned the basic behavior of the tangent function, let's look at its graph to learn even more:
Another element of the tangent function we can notice from this graph is that it is always increasing. Even though the value of the tangent function resets to negative infinity every time there is an asymptote, the function is still increasing.
The reason that the range of the tangent function is negative infinity to infinity is because we cannot divide by 0. In the denominator, we can divide by 0.01, 0.001, 0.0001, and keep adding zeroes forever. This is why the graph goes to positive and negative infinity; because we can get infinitely close to zero in the denominator, but we cannot reach it and keep the function continuous.
Now that we have explored the fundamentals of the tangent function, we can use those fundamentals to transform the tangent function and find the equations.
The general equation for a tangent function is much the same as the equation for a sinusoidal function:
The amplitude of a function is a measure of how much the function oscillates above and below the center line or the x-axis. In this case, the amplitude of the tangent function is "a". The amplitude of the tangent function is the absolute value of "a" and determines the vertical dilation of the tangent function. If the value of "a" is negative, the function has been reflected over the x-axis.
The period of a function is the interval over which the function repeats itself. For the tangent function, the period is T = π/b. The smaller the value of "b", the wider the function gets and the greater the period is.
The phase shift of a function is a measure of how much the function is shifted horizontally. In this case, the phase shift of the tangent function is c. If c is positive, the graph is shifted to the right, and if c is negative, the graph is shifted to the left.
The vertical shift of a function is a measure of how much the function is shifted vertically. In this case, the vertical shift of the tangent function is d. If d is positive, the graph is shifted up, and if d is negative, the graph is shifted down.
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Kashvi Panjolia
Kashvi Panjolia
In the past few guides, we have been focusing on sinusoidal functions -- functions that look like the sine and cosine curves. In this guide, we will return to the unit circle to explore a third function that is not sinusoidal -- the tangent function. Then, we'll put together the ideas we learned about the transformation of sinusoidal functions and see how they apply to the non-sinusoidal function of tangent.
The tangent function, denoted by the symbol "tan", is a trigonometric function that is commonly used in mathematics and physics. It is defined as the ratio of the length of the side opposite a given angle in a right triangle to the length of the side adjacent to that angle. In other words, if a right triangle has an angle θ, with opposite side y and adjacent side x, the tangent of that angle is defined as tan(θ) = y/x.
x = cos(θ) and y = sin(θ)
Like we did for sine and cosine, let's understand the behavior of the tangent function using patterns we find on the unit circle. As we move around the unit circle, the value of θ changes, and the coordinates (x, y) change. As a result, the equation f(θ) = tan(θ) traces out the graph of the tangent function. Starting at the 0-degree mark, and moving counterclockwise, we can see that the values for sin(θ)/cos(θ) are increasingly positive for the first quadrant. At θ = 𝛑/2, the value of sin(θ)/cos(θ) is 1/0, so the slope is--
Wait. We can't divide by 0!
This is where the behavior of the tangent function differs from sine and cosine. As you probably learned in algebra, the slope of a vertical line, such as the one created by the terminal ray at θ = 𝛑/2, is undefined. This means that at θ = 𝛑/2, there is a vertical asymptote in the graph of tangent. We'll come back to this in a moment. Let's continue analyzing the patterns we see in the unit circle.
Moving from θ = 𝛑/2 to θ = 𝛑, we see that the tangent values are negative, but increasing towards 0. In the third quadrant, the tangent values are positive (again?) because a negative divided by a negative becomes positive. At θ = 3𝛑/2, we have to divide -1 by 0, which is, again, not possible, so our slope is once again undefined. In the fourth quadrant, the values of tangent are once again negative and increasing.
Recall that the slope of the terminal ray is equal to the tangent of the angle. If you zoom out and look at the unit circle as a whole, you'll notice that the angles θ = 𝛑/6 and θ = 7𝛑/6 lie along the same line. This means that the two terminal rays pointing to these two angles have the same slope, and therefore, the tangent value of these two angles is the same. Based on this observation, the tangent function repeats every half-rotation around the unit circle, so it has a period of 𝛑, whereas the sine and cosine functions had a period of 2𝛑.
Now that we have learned the basic behavior of the tangent function, let's look at its graph to learn even more:
Another element of the tangent function we can notice from this graph is that it is always increasing. Even though the value of the tangent function resets to negative infinity every time there is an asymptote, the function is still increasing.
The reason that the range of the tangent function is negative infinity to infinity is because we cannot divide by 0. In the denominator, we can divide by 0.01, 0.001, 0.0001, and keep adding zeroes forever. This is why the graph goes to positive and negative infinity; because we can get infinitely close to zero in the denominator, but we cannot reach it and keep the function continuous.
Now that we have explored the fundamentals of the tangent function, we can use those fundamentals to transform the tangent function and find the equations.
The general equation for a tangent function is much the same as the equation for a sinusoidal function:
The amplitude of a function is a measure of how much the function oscillates above and below the center line or the x-axis. In this case, the amplitude of the tangent function is "a". The amplitude of the tangent function is the absolute value of "a" and determines the vertical dilation of the tangent function. If the value of "a" is negative, the function has been reflected over the x-axis.
The period of a function is the interval over which the function repeats itself. For the tangent function, the period is T = π/b. The smaller the value of "b", the wider the function gets and the greater the period is.
The phase shift of a function is a measure of how much the function is shifted horizontally. In this case, the phase shift of the tangent function is c. If c is positive, the graph is shifted to the right, and if c is negative, the graph is shifted to the left.
The vertical shift of a function is a measure of how much the function is shifted vertically. In this case, the vertical shift of the tangent function is d. If d is positive, the graph is shifted up, and if d is negative, the graph is shifted down.
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