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2 min readβ’june 18, 2024
Dalia Savy
Dalia Savy
Welcome to the first key topic of Unit 3! In this key topic, weβll learn more about taking derivatives of functions within functions, also known as composite functions. If you need a review on how to take derivatives, review Unit 2!
Yep! Composite functions are functions within functions, but what does this mean?
Given two functions and , the composite function is formed by applying function to the output of function .
Mathematically, the composite function is expressed as:. You can basically think of as the βinner functionβ and as the βouter function.β
Letβs consider the following two functions:
If weβre taking a look at the composite function , we have to be able to identify the inner function and the outer function. Letβs do that now! β¬οΈ
Therefore, we can think of this example as the following:
Understanding how composite functions work is crucial in the chain rule. Now letβs get into it!
The Chain Rule is a method of differentiation, just like the Power Rule, Product Rule, and Quotient Rule from the previous unit. There are two notations for the Chain Rule.
Letβs go through each piece of this:
The next notation will make this all clearer! ππΏ
As you can see, in order to take the derivative of the composite function, you are taking the derivative from the outside β¬ οΈ to the inside β‘οΈ. This will repeat if there is another function within .
To help break the chain rule down, follow these steps:
Hereβs a little graphic as well to help you visualize the chain rule.
Find the derivative of the following function with respect to .
1οΈβ£ Define your inner and outer functions.
The inner function is . The outer function is .
2οΈβ£ Take the derivative of the outer function only!
As you can see, we have not taken the derivative of the inner function yet.
3οΈβ£ Take the derivative of the inner function with respect to .
4οΈβ£ Now multiply the two derivatives to get your final answer!
Let and . Find the derivative of with respect to .
1οΈβ£ Define your inner and outer functions.
In this problem, they are more explicit! is the outer function and is the inner function.
2οΈβ£ Take the derivative of the outer function.
The derivative of is just !
3οΈβ£ Take the derivative of the inner function with respect to .
4οΈβ£ Then multiply the two derivatives to get your final answer!
Find the derivative of the following function; this one may be a bit tougher!
1οΈβ£ Define your inner and outer functions.
The inner function is and the outer function is .
2οΈβ£ Take the derivative of the outer function.
3οΈβ£ Take the derivative of the inner function with respect to .
4οΈβ£ Now multiply the two derivatives to get your final answer!
How about a function with a square root?
1οΈβ£ Define your inner and outer functions.
The inner function is and the outer function is .
2οΈβ£ Take the derivative of the outer function.
3οΈβ£ Take the derivative of the inner function with respect to .
4οΈβ£ Now multiply the two derivatives to get your final answer!
Try taking the derivative of the following function yourself!
To help you out a little, the inner function is and the outer function is .
Hereβs the answer:
You made it through the first section of the unit! From now to the rest of your AP Calculus journey, the Chain Rule will accompany you and with practice, you will get to perfection! π
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2 min readβ’june 18, 2024
Dalia Savy
Dalia Savy
Welcome to the first key topic of Unit 3! In this key topic, weβll learn more about taking derivatives of functions within functions, also known as composite functions. If you need a review on how to take derivatives, review Unit 2!
Yep! Composite functions are functions within functions, but what does this mean?
Given two functions and , the composite function is formed by applying function to the output of function .
Mathematically, the composite function is expressed as:. You can basically think of as the βinner functionβ and as the βouter function.β
Letβs consider the following two functions:
If weβre taking a look at the composite function , we have to be able to identify the inner function and the outer function. Letβs do that now! β¬οΈ
Therefore, we can think of this example as the following:
Understanding how composite functions work is crucial in the chain rule. Now letβs get into it!
The Chain Rule is a method of differentiation, just like the Power Rule, Product Rule, and Quotient Rule from the previous unit. There are two notations for the Chain Rule.
Letβs go through each piece of this:
The next notation will make this all clearer! ππΏ
As you can see, in order to take the derivative of the composite function, you are taking the derivative from the outside β¬ οΈ to the inside β‘οΈ. This will repeat if there is another function within .
To help break the chain rule down, follow these steps:
Hereβs a little graphic as well to help you visualize the chain rule.
Find the derivative of the following function with respect to .
1οΈβ£ Define your inner and outer functions.
The inner function is . The outer function is .
2οΈβ£ Take the derivative of the outer function only!
As you can see, we have not taken the derivative of the inner function yet.
3οΈβ£ Take the derivative of the inner function with respect to .
4οΈβ£ Now multiply the two derivatives to get your final answer!
Let and . Find the derivative of with respect to .
1οΈβ£ Define your inner and outer functions.
In this problem, they are more explicit! is the outer function and is the inner function.
2οΈβ£ Take the derivative of the outer function.
The derivative of is just !
3οΈβ£ Take the derivative of the inner function with respect to .
4οΈβ£ Then multiply the two derivatives to get your final answer!
Find the derivative of the following function; this one may be a bit tougher!
1οΈβ£ Define your inner and outer functions.
The inner function is and the outer function is .
2οΈβ£ Take the derivative of the outer function.
3οΈβ£ Take the derivative of the inner function with respect to .
4οΈβ£ Now multiply the two derivatives to get your final answer!
How about a function with a square root?
1οΈβ£ Define your inner and outer functions.
The inner function is and the outer function is .
2οΈβ£ Take the derivative of the outer function.
3οΈβ£ Take the derivative of the inner function with respect to .
4οΈβ£ Now multiply the two derivatives to get your final answer!
Try taking the derivative of the following function yourself!
To help you out a little, the inner function is and the outer function is .
Hereβs the answer:
You made it through the first section of the unit! From now to the rest of your AP Calculus journey, the Chain Rule will accompany you and with practice, you will get to perfection! π
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